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28x^2+36x+8=0
a = 28; b = 36; c = +8;
Δ = b2-4ac
Δ = 362-4·28·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-20}{2*28}=\frac{-56}{56} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+20}{2*28}=\frac{-16}{56} =-2/7 $
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